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5.6=1.5x^2
We move all terms to the left:
5.6-(1.5x^2)=0
We get rid of parentheses
-1.5x^2+5.6=0
a = -1.5; b = 0; c = +5.6;
Δ = b2-4ac
Δ = 02-4·(-1.5)·5.6
Δ = 33.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{33.6}}{2*-1.5}=\frac{0-\sqrt{33.6}}{-3} =-\frac{\sqrt{}}{-3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{33.6}}{2*-1.5}=\frac{0+\sqrt{33.6}}{-3} =\frac{\sqrt{}}{-3} $
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